\u0110\u00e1nh l\u00f4 xi\u00ean l\u00e0 c\u00f9ng l\u00fac ch\u1ecdn \u0111\u00e1nh nhi\u1ec1u s\u1ed1 kh\u00e1c nhau, khi t\u1ea5t c\u1ea3 c\u00f9ng ra s\u1ed1 th\u00ec s\u1ebd \u0103n, nh\u01b0ng hi\u1ec7n nay c\u00f3 kh\u00f4ng \u00edt ng\u01b0\u1eddi \u0111\u00e1nh l\u00f4 xi\u00ean ch\u1ec9 nh\u0103m nh\u0103m quan t\u00e2m \u0111\u1ebfn khi tr\u00fang ph\u1ea7n th\u01b0\u1edfng nh\u01b0 th\u1ebf n\u00e0o c\u00f2n kh\u00f4ng bi\u1ebft \u0111\u1ebfn \u0111\u1ed9 kh\u00f3 khi ch\u01a1i l\u00f4 xi\u00ean. B\u1edfi \u0111\u00e1nh l\u00f4 xi\u00ean chi ph\u00ed th\u1ea5p thu h\u00fat nhi\u1ec1u ng\u01b0\u1eddi ch\u01a1i.<\/p>\n
L\u00e0m th\u1ebf n\u00e0o \u0111\u1ec3 bi\u1ebft \u0111\u01b0\u1ee3c \u0111\u1ed9 kh\u00f3 khi ch\u01a1i l\u00f4 xi\u00ean? \u0110\u1ea7u ti\u00ean, ch\u00fang ta ph\u1ea3i bi\u1ebft x\u00e1c su\u1ea5t \u0111\u00e1nh l\u00f4 xi\u00ean.<\/p>\n
Nh\u01b0 c\u00e1c b\u1ea1n \u0111\u00e3 bi\u1ebft, c\u00f3 27 gi\u1ea3i k\u1ebft qu\u1ea3 x\u1ed5 s\u1ed1, nh\u01b0ng th\u1ed1ng k\u00ea ch\u00fang t\u00f4i t\u1ed5ng k\u1ebft \u0111\u01b0\u1ee3c ch\u1ec9 c\u00f3 21,5 s\u1ed1 kh\u00e1c nhau. Do \u0111\u00f3, x\u00e1c su\u1ea5t \u0111\u1ec3 \u0111\u00e1nh con b\u1ea1ch th\u1ee7 m\u1ed9t s\u1ed1 duy nh\u1ea5t hay c\u00f2n g\u1ecdi xi\u00ean 1 l\u00e0 21,5%. V\u1eady b\u1ea1n th\u1ea5y d\u1ec5 hay kh\u00f3? B\u00ecnh qu\u00e2n 5 s\u1ed1 may ra c\u00f3 1 s\u1ed1 tr\u00fang m\u00e0 x\u00e1c su\u1ea5t \u0103n \u0111\u01b0\u1ee3c l\u00f4 xi\u00ean 1 nh\u1ecf h\u01a1n ch\u01a1i x\u00f3c \u0111\u0129a t\u1edbi 2,5 l\u1ea7n v\u00ec x\u00f3c \u0111\u0129a c\u00f3 x\u00e1c su\u1ea5t ch\u01a1i th\u1eafng \u0111\u1ebfn 50%.<\/p>\n
C\u00f2n v\u1edbi xi\u00ean 2, x\u00e1c su\u1ea5t \u0111\u00e1nh tr\u00fang l\u00e0 21,5% x 21,5% = 0,0462 -> x\u00e1c su\u1ea5t \u0111\u00e1nh tr\u00fang ch\u1ec9 c\u00f3 4,6%.<\/p>\n
L\u00f4 xi\u00ean 3 x\u00e1c xu\u1ea5t tr\u00fang b\u1eb1ng 21,5% x 21,5% x 21,5% =00994 -> x\u00e1c su\u1ea5t \u0111\u00e1nh tr\u00fang c\u00f3 0,994%.<\/p>\n
C\u00c1CH \u0110\u00c1NH TH\u1eaeNG L\u00d4 XI\u00caN<\/h4>\n
Khi \u0111\u00e1nh l\u00f4 xi\u00ean, m\u1ecdi ng\u01b0\u1eddi n\u00ean bi\u1ebft nh\u1eefng con s\u1ed1 n\u00e0o hay r\u1ee7 nhau c\u00f9ng ra. D\u1ef1a v\u00e0o nh\u1eefng con s\u1ed1 \u0111\u00f3, ng\u01b0\u1eddi \u0111\u00e1nh l\u00f4 xi\u00ean r\u1ea5t d\u1ec5 tr\u00fang b\u1edfi th\u1ef1c t\u1ebf cho th\u1ea5y m\u1ed9t con s\u1ed1 th\u01b0\u1eddng hay ra c\u00f9ng v\u1edbi m\u1ed9t v\u00e0i con s\u1ed1 kh\u00e1c.<\/p>\n
C\u00e1c con l\u00f4 hay ra h\u1eb1ng ng\u00e0y nh\u1ea5t: 75-79-92-373-565<\/p>\n
C\u00e1c c\u1eb7p l\u00f4 hay \u0111i k\u00e8m nhau: 373-010; 25 ho\u1eb7c 52-22; 76-47; 11-44; 33-66.<\/p>\n
L\u00f4 ra c\u1ea3 c\u1eb7p 060 th\u00ec h\u00f4m sau s\u1ebd r\u01a1i l\u1ea1i 1 s\u1ed1<\/p>\n
H\u00f4m tr\u01b0\u1edbc c\u00f3 l\u00f4 51 th\u00ec h\u00f4m sau c\u00f3 l\u00f4 15 ho\u1eb7c c\u00f3 c\u1ea3 c\u1eb7p 15 v\u00e0 51<\/p>\n
L\u00f4 ra c\u1ea3 c\u1eb7p 05 v\u00e0 50 ho\u1eb7c \u0111\u1ed5 1 con th\u00ec h\u00f4m sau s\u1ebd \u0111\u1ed5 l\u1ea1i 1 con.<\/p>\n
L\u00f4 ra c\u1ea3 c\u1eb7p 02 v\u00e0 20 ho\u1eb7c h\u00f4m tr\u01b0\u1edbc \u0111\u1ed5 1 con th\u00ec h\u00f4m sau s\u1ebd \u0111\u1ed5 l\u1ea1i 1 con.<\/p>\n
C\u00f3 l\u00f4 \u0111\u1ea7u 7 hay l\u00f4 \u0111\u00edt 3 m\u00e0 c\u00e2m th\u00ec h\u00f4m sau s\u1ebd v\u1ec1 con 73.<\/p>\n
Ng\u00e0y h\u00f4m tr\u01b0\u1edbc c\u00f3 con l\u00f4 97 th\u00ec h\u00f4m sau c\u00f3 l\u00f4 373<\/p>\n
Th\u1ee9 5 v\u00e0 th\u1ee9 7 th\u01b0\u1eddng hay ra l\u00f4 97<\/p>\n
Con l\u00f4 33 th\u01b0\u1eddng ra v\u00e0o m\u1ed9t trong 2 ng\u00e0y 2 cu\u1ed1i tu\u1ea7n v\u00e0 2 ng\u00e0y \u0111\u1ea7u tu\u1ea7n.<\/p>\n
L\u00f4 66 hay v\u1ec1 ng\u00e0y th\u1ee9 4, th\u1ee9 5, ho\u1eb7c th\u1ee9 6.<\/p>\n
Ng\u00e0y h\u00f4m tr\u01b0\u1edbc c\u00f3 con l\u00f4 18 th\u00ec h\u00f4m sau s\u1ebd c\u00f3 l\u00f4 97 ho\u1eb7c 99 v\u00e0 ng\u01b0\u1ee3c l\u1ea1i.<\/p>\n
L\u00f4 58 m\u00e0 ra th\u00ec 3 ng\u00e0y sau s\u1ebd c\u00f3 l\u00f4 63.<\/p>\n
Ng\u00e0y h\u00f4m tr\u01b0\u1edbc \u0111\u1ec1 v\u1ec1 05 th\u00ec h\u00f4m sau s\u1ebd c\u00f3 l\u00f4 95, v\u1ec1 29 th\u00ec h\u00f4m sau c\u00f3 l\u00f4 22 ho\u1eb7c ng\u01b0\u1ee3c l\u1ea1i.<\/p>\n
\u0110\u1ec1 v\u1ec1 k\u00e9p th\u00ec h\u00f4m sau s\u1ebd xu\u1ea5t hi\u1ec7n 1 trong c\u00e1c con l\u00f4 sau: 010-060-151-565. C\u00e1ch \u0111\u00f3 1 tu\u1ea7n s\u1ebd ra l\u00f4 1 trong c\u00e1c s\u1ed1 sau: 232-282-373-787.<\/p>\n<\/div>\n<\/div>\n
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